Class 8 Maths Chapter 7 Area MCQs for Exam Preparation | Ganita Prakash Part 2

Preparing for your Maths exam becomes much easier when you practise questions based on the latest syllabus. If you are searching for Class 8 Maths Area Chapter 7 MCQs with Answers, this page is the perfect place to begin your revision. It is specially designed for students following the CBSE Board Class 8 Maths Ganita Prakash Part 2 textbook and helps you revise the chapter through important objective questions.

Chapter 7 Area teaches you how to calculate the area of different two-dimensional shapes by understanding the concepts instead of simply memorising formulas. In this chapter, you will learn about the area of triangles, parallelograms, trapeziums, rhombuses, and composite figures. You will also understand the difference between area and perimeter and learn how to apply these ideas in practical situations.

The Class 8 Maths Area Chapter 7 MCQs with Answers on this page are useful for class tests, unit tests, half-yearly examinations, annual examinations, and Olympiad-level practice. Solve each question carefully and check the answer only after attempting it yourself. This method helps improve both accuracy and confidence.

If you want to practise more chapter-wise questions, explore our MCQs collection for different subjects. You can also visit our Class 8 MCQs page for subject-wise practice or check our Class 8 Maths MCQs section to revise every chapter of the latest CBSE syllabus in one place.

Practice MCQs of Class 8 Maths Chapter 7 Area

Practise the following Class 8 Maths Area Chapter 7 MCQs with Answers to test your understanding of the chapter and improve your exam preparation. The questions are arranged from basic concepts to higher-order thinking so that you can gradually build confidence while revising. Each question includes the correct answer and a short explanation to help you understand the concept clearly.

Q. The base of a triangle is 18 cm and its height is 14 cm. A parallelogram has the same base and height. What is the difference between their areas?

A. 126 cm²

B. 252 cm²

C. 144 cm²

D. 108 cm²

Answer: A. 126 cm²

Explanation:
Area of triangle = (1/2) × 18 × 14 = 126 cm²
Area of parallelogram = 18 × 14 = 252 cm²
Difference = 252 − 126 = 126 cm².

Q. A rectangle has length 18 cm and breadth 12 cm. A path of uniform width 1 cm is built inside all four sides. What is the area of the path?

A. 52 cm²

B. 56 cm²

C. 60 cm²

D. 64 cm²

Answer: B. 56 cm²

Explanation:
Outer area = 18 × 12 = 216 cm²
Inner dimensions = 16 cm × 10 cm
Inner area = 160 cm²
Area of path = 216 − 160 = 56 cm².

Q. The diagonals of a rhombus are 18 cm and 24 cm. Its area is:

A. 196 cm²

B. 204 cm²

C. 216 cm²

D. 224 cm²

Answer: C. 216 cm²

Explanation:
Area of rhombus = (1/2) × d₁ × d₂
= (1/2) × 18 × 24 = 216 cm².

Q. A trapezium has parallel sides of 16 cm and 28 cm. If its height is 9 cm, what is its area?

A. 180 cm²

B. 192 cm²

C. 198 cm²

D. 210 cm²

Answer: C. 198 cm²

Explanation:
Area = (1/2) × (16 + 28) × 9
= (1/2) × 44 × 9
= 198 cm².

Q. A triangle and a parallelogram have equal areas. If the parallelogram has base 15 cm and height 12 cm, the triangle has the same height. What is the base of the triangle?

A. 15 cm

B. 24 cm

C. 30 cm

D. 36 cm

Answer: C. 30 cm

Explanation:
Area of parallelogram = 15 × 12 = 180 cm²

For the triangle,

(1/2) × Base × 12 = 180

Base = 30 cm.

Q. A square has the same area as a rectangle of length 20 cm and breadth 5 cm. What is the side of the square?

A. 8 cm

B. 10 cm

C. 12 cm

D. 15 cm

Answer: B. 10 cm

Explanation:
Area of rectangle = 20 × 5 = 100 cm²

Side of square = √100 = 10 cm.

Q. A triangle has an area of 108 cm². If its base is increased from 12 cm to 18 cm while keeping the area unchanged, what will be the new height?

A. 10 cm

B. 11 cm

C. 12 cm

D. 14 cm

Answer: C. 12 cm

Explanation:
Area = (1/2) × Base × Height

108 = (1/2) × 18 × Height

108 = 9 × Height

Height = 12 cm.

Q. A rectangular field measures 50 m × 30 m. A square lawn of side 20 m is made inside it. What is the remaining area?

A. 1000 m²

B. 1050 m²

C. 1100 m²

D. 1200 m²

Answer: C. 1100 m²

Explanation:
Area of rectangle = 50 × 30 = 1500 m²

Area of square  = 20 × 20 = 400 m²

Remaining area = 1500 − 400 = 1100 m².

Q. A parallelogram has base 24 cm and area 288 cm². What is its perpendicular height?

A. 10 cm

B. 11 cm

C. 12 cm

D. 14 cm

Answer: C. 12 cm

Explanation:
Area = Base × Height

288 = 24 × Height

Height = 12 cm.

Q. An irregular figure is divided into a rectangle of area 96 cm² and a triangle of area 24 cm². What is the total area of the figure?

A. 110 cm²

B. 118 cm²

C. 120 cm²

D. 122 cm²

Answer: C. 120 cm²

Explanation:
Total area = Area of rectangle + Area of triangle

= 96 + 24

= 120 cm².

Q. A triangle has a base of 16 cm and an area of 120 cm². What is its height?

A. 12 cm

B. 15 cm

C. 16 cm

D. 18 cm

Answer: B. 15 cm

Explanation:
Area = (1/2) × Base × Height

120 = (1/2) × 16 × Height

120 = 8 × Height

Height = 15 cm.

Q. A parallelogram and a rectangle have the same base and the same height. Which statement is always true?

A. The rectangle has a greater area.

B. The parallelogram has a greater area.

C. Both have the same area.

D. Their areas cannot be compared.

Answer: C. Both have the same area.

Explanation:
The area of both a rectangle and a parallelogram is calculated using the same formula:

Area = Base × Height.

Q. The diagonals of a rhombus are 30 cm and 16 cm. What is its area?

A. 220 cm²

B. 240 cm²

C. 260 cm²

D. 280 cm²

Answer: B. 240 cm²

Explanation:
Area = (1/2) × 30 × 16

= 15 × 16

= 240 cm².

Q. A trapezium has parallel sides of 20 cm and 14 cm. If its area is 170 cm², what is its height?

A. 8 cm

B. 9 cm

C. 10 cm

D. 12 cm

Answer: C. 10 cm

Explanation:
Area = (1/2) × (20 + 14) × Height

170 = 17 × Height

Height = 10 cm.

Q. A rectangle measures 28 cm × 18 cm. A smaller rectangle of dimensions 16 cm × 8 cm is removed from one corner. What is the area of the remaining figure?

A. 364 cm²

B. 376 cm²

C. 392 cm²

D. 408 cm²

Answer: B. 376 cm²

Explanation:
Area of large rectangle = 28 × 18 = 504 cm²

Area removed = 16 × 8 = 128 cm²

Remaining area = 504 − 128 = 376 cm².

Q. The base of a triangle is doubled while its height remains the same. What happens to its area?

A. It becomes half.

B. It remains unchanged.

C. It becomes double.

D. It becomes four times.

Answer: C. It becomes double.

Explanation:
Since Area = (1/2) × Base × Height, doubling the base doubles the area.

Q. A square has an area of 289 cm². What is its perimeter?

A. 64 cm

B. 68 cm

C. 72 cm

D. 76 cm

Answer: B. 68 cm

Explanation:
Side = √289 = 17 cm

Perimeter = 4 × 17 = 68 cm.

Q. A triangular garden has a base of 30 m and a height of 18 m. Grass costs ₹12 per square metre. What is the total cost of covering the garden with grass?

A. ₹3,000

B. ₹3,120

C. ₹3,240

D. ₹3,360

Answer: C. ₹3,240

Explanation:
Area = (1/2) × 30 × 18 = 270 m²

Cost = 270 × ₹12 = ₹3,240.

Q. A rhombus has an area of 192 cm². One diagonal measures 24 cm. What is the length of the other diagonal?

A. 12 cm

B. 14 cm

C. 16 cm

D. 18 cm

Answer: C. 16 cm

Explanation:
192 = (1/2) × 24 × d

192 = 12d

d = 16 cm.

Q. A rectangle has a length of 32 cm and a breadth of 18 cm. A uniform path of width 2 cm is built inside all four sides. What is the area of the path?

A. 176 cm²

B. 184 cm²

C. 192 cm²

D. 200 cm²

Answer: B. 184 cm²

Explanation:
Outer area = 32 × 18 = 576 cm²

Since the path is 2 cm wide on all four sides, the inner rectangle measures:

Length = 32 − 4 = 28 cm
Breadth = 18 − 4 = 14 cm

Inner area = 28 × 14 = 392 cm²

Area of the path = 576 − 392 = 184 cm².

Q. A triangle and a parallelogram stand on the same base of 18 cm and have the same height of 12 cm. What is the sum of their areas?

A. 324 cm²

B. 216 cm²

C. 162 cm²

D. 108 cm²

Answer: A. 324 cm²

Explanation:
Area of parallelogram = 18 × 12 = 216 cm²

Area of triangle = (1/2) × 18 × 12 = 108 cm²

Sum = 216 + 108 = 324 cm².

Q. A trapezium has an area of 240 cm². Its parallel sides are 18 cm and 30 cm. What is its height?

A. 8 cm

B. 10 cm

C. 12 cm

D. 15 cm

Answer: B. 10 cm

Explanation:
Area = (1/2) × (18 + 30) × Height

240 = (1/2) × 48 × Height

240 = 24 × Height

Height = 10 cm.

Q. A square and a rectangle have the same area. The rectangle measures 25 cm × 16 cm. What is the side of the square?

A. 18 cm

B. 19 cm

C. 20 cm

D. 22 cm

Answer: C. 20 cm

Explanation:
Area of rectangle = 25 × 16 = 400 cm²

Side of square = √400 = 20 cm.

Q. The diagonals of a rhombus are in the ratio 3 : 4. If its area is 216 cm², what are the lengths of the diagonals?

A. 18 cm and 24 cm

B. 12 cm and 36 cm

C. 16 cm and 27 cm

D. 20 cm and 30 cm

Answer: A. 18 cm and 24 cm

Explanation:
Let the diagonals be 3x and 4x.

Area = (1/2) × 3x × 4x = 6x²

216 = 6x²

x² = 36

x = 6

Diagonals = 18 cm and 24 cm.

Q. A rectangular park is 60 m long and 40 m wide. A walking path of width 5 m is made all around the inside of the park. What is the area of the walking path?

A. 800 m²

B. 850 m²

C. 900 m²

D. 950 m²

Answer: C. 900 m²

Explanation:
Outer area = 60 × 40 = 2400 m²

Inner dimensions = 50 m × 30 m

Inner area = 1500 m²

Area of path = 2400 − 1500 = 900 m².

Q. A triangle has an area of 150 cm² and a height of 15 cm. What is its base?

A. 18 cm

B. 20 cm

C. 22 cm

D. 24 cm

Answer: B. 20 cm

Explanation:
150 = (1/2) × Base × 15

300 = 15 × Base

Base = 20 cm.

Q. An irregular figure consists of a rectangle of area 180 cm² and two congruent triangles, each having an area of 24 cm². What is the total area of the figure?

A. 204 cm²

B. 216 cm²

C. 228 cm²

D. 240 cm²

Answer: C. 228 cm²

Explanation:
Total area = 180 + 24 + 24 = 228 cm².

Q. A parallelogram has a base of 36 cm and an area of 504 cm². If its base is increased by 6 cm while the area remains unchanged, what will be the new height?

A. 10 cm

B. 11 cm

C. 12 cm

D. 14 cm

Answer: C. 12 cm

Explanation:
New base = 36 + 6 = 42 cm

Height = Area ÷ Base

= 504 ÷ 42

= 12 cm.

Q. A rectangle measures 24 cm × 18 cm. A square of side 6 cm is removed from each of its four corners. What is the remaining area?

A. 264 cm²

B. 276 cm²

C. 288 cm²

D. 300 cm²

Answer: C. 288 cm²

Explanation:
Area of rectangle = 24 × 18 = 432 cm²

Area removed = 4 × (6 × 6)

= 4 × 36 = 144 cm²

Remaining area = 432 − 144 = 288 cm².

Q. A composite figure is formed by joining a rectangle of dimensions 20 cm × 12 cm and a triangle with base 20 cm and height 8 cm along one side. What is the total area of the figure?

A. 300 cm²

B. 320 cm²

C. 340 cm²

D. 360 cm²

Answer: B. 320 cm²

Explanation:
Area of rectangle = 20 × 12 = 240 cm²

Area of triangle = (1/2) × 20 × 8 = 80 cm²

Total area = 240 + 80 = 320 cm².

Chapter 7 Area One-Minute Revision Notes

Revise these important points before attempting the MCQs or appearing for your examination.

Important Formulas

• Area of Rectangle = Length × Breadth
• Area of Square = Side × Side
• Area of Triangle = 1/2 × Base × Height
• Area of Parallelogram = Base × Height
• Area of Trapezium = 1/2 × (Sum of Parallel Sides) × Height
• Area of Rhombus = 1/2 × Diagonal 1 × Diagonal 2

Important Definitions

Area: The amount of surface enclosed inside a closed figure. It is measured in square units such as cm² or m².

Perimeter: The total length of the boundary of a closed figure.

Base: The side of a figure chosen to calculate its area.

Height (Altitude): The perpendicular distance from the base to the opposite side or vertex.

Composite Figure: A shape made by combining two or more simple figures.

Diagonal: A line segment joining two non-adjacent vertices of a polygon.

Important Rules

• Always use the perpendicular height while finding the area.
• Write the final answer in square units.
• Convert all measurements into the same unit before calculating.
• Use the correct formula for each shape.
• Divide by 2 only where the formula requires it.
• Break complex figures into simpler shapes whenever possible.
• Check your calculations before choosing the final answer.

Important Terms

• Area
• Perimeter
• Base
• Height
• Altitude
• Triangle
• Rectangle
• Square
• Parallelogram
• Trapezium
• Rhombus
• Polygon
• Composite Figure
• Diagonal
• Square Units

Difficulty Level of These MCQs

Best Way to Practise Class 8 CHapter 7 Area MCQs

Getting the correct answer is important, but understanding why it is correct is even more valuable. Follow these simple steps to make your practice more effective.

• Read the complete question carefully before solving it.
• Try to answer every MCQ without looking at the answer first.
• Draw a rough figure whenever the question involves a geometric shape.
• Revise the formula before solving calculation-based questions.
• Compare your answer with the correct solution and understand your mistakes.
• Mark the questions you find difficult and practise them again later.
• Before your exam, solve all the MCQs once more to improve speed and confidence.